MySQL parse error

[russia5]

I am trying to get this little code working.



<?php
mysql_connect("localhost", "russia5_Greg", "pasadena1") or die(mysql_error());
echo "Connected to MySQL
";
mysql_select_db("russia5_profiles") or die(mysql_error());
or die(mysql_error());
$rows_per_page = 3;
$sql = "SELECT * FROM Profile_delivery";
$result = mysql_query($sql, $db);
$total_records = mysql_num_rows($result);
$pages = ceil($total_records / $rows_per_page);
mysql_free_result($result);
?>

I get this error in my browser


Parse error: parse error in /home/russia5/public_html/index_Greg6.php on line 107


Anybody know why? Greg

[LarsLai]

hi!
perhaps it`s just this - after

mysql_select_db("russia5_profiles") or die(mysql_error());

you have another

or die(mysql_error());

i think the parser will not like an "or" at the beginning of a line.