Date validation

[achilleas]

Hi. I am trying to cut the portions of a date XX/XX/XXXX where Xs are numbers

This is a portion of my code:

$date = "9/2/1983";
$pos1 = strpos($date, "/");
$pos2 = strpos($date, "/", $pos1+1);
echo $pos1."
";
echo $pos2."
";
$day = substr($date, 0, $pos1);
$month = substr($date, $pos1+1, $pos2-1);
$year = substr($date, $pos2+1, strlen($date));


it seems that i cannot get the month correctly. I can't understand why.
Note that the date will be entered from a form and will have a british type (Day/Month/Year).

help!!! )

Thank you

[Xnuiem]

$date = explode("/", "9/2/1983");
$day = $date[0];
$month = $date[1];
$year = $date[2];

http://www.php.net/explode

hi

Xnuiem (congrats...) definitely showed you the best and quickest solution for parsing strings.
anyway, in case you'd like to find out more about the mess with 0-based/1-based functions,
send me a note, i've built a code-snippet which i can send you. the most important thing
in the behaviour of some functions is to understand the difference they handle position and length.
positions are 0-based, which means you have to deal with a calculation-base of zero (real offset 1 is 0).
lengths are 1-based (real).

$month  = substr($testdate, $start1, $len1);
                       |      |__________ 1-based
                       |_________________ 0-based

Beat
(Beat is a firstname here in Switzerland, so don't feel bothered...)

[beath]

sorry i wasn't logged in before. my nick is beath if you want the code-snippet

Originally posted by beath@Jun 28 2004, 08:25 AM
i would like to view how the date field validation is going

:huh: